Both ends of an aluminum rod of length 20 cm and cross-sectional area 4" cm"^(2) are kept at a temperature 0^(@)C. Thermal conductivity of aluminum is 205 W/(m-k). The initial distribution of temperature along the rod can be expressed as T=75sin(15.7x)""^(@)C. Here, length of the rod has been considered to be along the X direction and one of the ends as the origin so that .x. in the initial temperature distribution equation refers to the x position of any point on the rod. Also the angle in the sin term is in radian provided that x is expressed in the SI system Initial temperature distribution along the length of rod is given above. Final temperature distribution after a long time, can be expressed as

Both ends of an aluminum rod of length 20 cm and cross-sectional area

1.	Both ends of an aluminum rod of length 20 cm and cross-sectional area 4" cm"^(2) are kept at a temperature 0^(@)C. Thermal conductivity of aluminum is 205 W/(m-k). The initial distribution of temperature along the rod can be expressed as T=75sin(15.7x)""^(@)C. Here, length of the rod has been considered to be along the X direction and one of the ends as the origin so that .x. in the initial temperature distribution equation refers to the x position of any point on the rod. Also the angle in the sin term is in radian provided that x is expressed in the SI system Initial temperature distribution along the length of rod is given above. Final temperature distribution after a long time, can be expressed as
Answer» `T=75cos(15.7x)""^(@)C` `T=25""^(@)C` `T=75tan(15.7x)""^(@)C` `T=0""^(@)C` ANSWER :D