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Both HCOOH and `CH_(3)COOH` solutions have equal pH. If `K_(1) // K_(2)` ( ration of acid ionisation constants ) of these acids is 4, their molar concentration ratio will beA. 2B. 0.5C. 0.05D. 0.25 |
Answer» Correct Answer - D As pH of HCOOH sol. `= pH` of `CH_(3)COOH` sol. `:. [H^(+)] ` in HCOOH sol. `=[H^(+)]` in `CH_(3)COOH` sol. `K_(1)=([HCOO^(-)][H^(+)])/([HOOH])=([H^(+)]^(2))/([HCOOH])` `K_(2)=([CH_(3)COO^(-)][H^(+)])/([CH_(3)COOH])=([H^(+)]^(2))/([CH_(3)COOH])` `K_(1)[HCOOH]=K_(2)[CH_(3)COOH]` `([HCOOH])/([CH_(3)COOH])=(K_(2))/(K_(1))=(1)/(4)=0.25` |
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