Saved Bookmarks
| 1. |
Both the strings, shown in figure, are made of same material and have same cross-section. The pulleys are light. The wave speed of transverse wave in the string `AB` is `v_(1)` and in `CD` it is `v_(2)`, the `v_(1)//v_(2)` is A. 1B. 2C. `sqrt2`D. `(1)/(sqrt2)` |
|
Answer» Correct Answer - D `v=sqrt((T)/(u))` [T = tension forse] [`mu` = mass per unit length] |
|