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Both the strings shown in figure are mode of same material and have same cross-section. The pulleys are light the wave speed of a transverse wave in the string AB is `v_(1)` and in CD it is `v_(2)`. Then `v_(1)//v_(2)` isA. 1B. 2C. `sqrt(2)`D. `1//sqrt(2)` |
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Answer» Correct Answer - D `v=sqrt((T)/(mu)): " "V_(AB)=sqrt((T)/(mu))" ",V_(CD)=sqrt((2T)/(mu))` |
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