1.

Boyle's law may be expressed as (one or more)

Answer»

<P>`(dP//dV)_(T)=K//V`
`(dP//dV)_(T)=-K//V^(2)`
`(dP//dV)_(T)=-K//V`
`V prop (1)/(p)`.

Solution :ACCORDING to Boyle's LAW, PV=K at constant T.
`:.` Ratio of mean SQUARE VELOCITIES, viz,
`:. "" P=K//V`
or`"" (dP//dV)=-K//V^(2)`.
Also `"" V prop 1//P`.


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