BrO_(3)^(-)+Br^(-)+H^(+)toBr_(2)+H_(2)O When this reaction is balanced completely, than mention the total charge and number of Bromine atoms on product respectively.

BrO_(3)^(-)+Br^(-)+H^(+)toBr_(2)+H_(2)O When this reaction is balance

1.	BrO_(3)^(-)+Br^(-)+H^(+)toBr_(2)+H_(2)O When this reaction is balanced completely, than mention the total charge and number of Bromine atoms on product respectively.
Answer» 0, 2 0, 6 `-1, 6` `-1, 2` Solution : (ii) Balancing change of oxidation number `BrO_(3)^(-)+5Br^(-)to1/2Br_(2)+5/2Br_(2)` `thereforeBrO_(3)^(-)+5Br^(-)to3Br_(2)` (iii) CHARGE, O and H balancing `BrO_(3)^(-)+5Br^(-)+6H^(+)=3Br_(2)+3H_(2)O` At product side : Total Charge = 0 No. of bromine ATOMS = 6