Saved Bookmarks
| 1. |
Bromine is added to cold dilute aqueous solution of NaOH. The mixture is boiled. Which of the following statements is not true ? |
|
Answer» During the REACTION bromine is present in four different oxidation states. `underset"Sodium hypobromide"(3NaBrO overset"300 K"to 3NaBrO)` On acidification, the final mixture gives bromine `5NaBrO+NaBrO_3 + 6HCl to 6NaCl + 3Br_2 + 3H_2O` Thus, during the reaction, bromine is present in four different oxidation states i.e., zero in `Br_2`, +1 in NaBrO, -1 in NaBr and +5 in `NaBrO_3`. The greatest difference between various oxidation states of bromine is 6 and not 5. On acidification of the final mixture, `Br_2` is formed and disproportionation of `Br_2` occurs during the reaction giving `BrO^(-), Br^(-)` and `BrO_3^-`IONS. |
|