1.

BU and find the length of EF6. In the given figure, D is the mid-point of ABLHand F is the mid-point of BC. Prove thatEF = DB7 In the iven figure, D. Fand F

Answer»

Given :DE||BC and D is midpoint of AB.

So, By converse of midpoint theorem E is midpoint of AC, Similarly F and E are midpoints of BC and AC respectively so, by midpoint theorem FE || AB, and EF = 1/2 AB So,EF = BD



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