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BU and find the length of EF6. In the given figure, D is the mid-point of ABLHand F is the mid-point of BC. Prove thatEF = DB7 In the iven figure, D. Fand F |
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Answer» Given :DE||BC and D is midpoint of AB. So, By converse of midpoint theorem E is midpoint of AC, Similarly F and E are midpoints of BC and AC respectively so, by midpoint theorem FE || AB, and EF = 1/2 AB So,EF = BD |
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