But for all arbitrary constants, `intsqrt((1+sintheta-sin^(2)theta-sin^(3)theta)/(2sintheta-1))d theta` is equal toA. `(1)/(2)sqrt(sin theta-cos2 theta)+(3)/(4sqrt(2))log_(e)|(4sintheta+1)+2sqrt(2)sqrt(sintheta-cos2theta)|`B. `(1)/(2)sqrt(sintheta+cos2theta)+(3)/(4sqrt(2))log_(e)|(4sin theta -1)+2sqrt(2)sqrt(sintheta+cos2 theta)|`C. `(1)/(2sqrt(2))sqrt(sintheta-cos2 theta)+(3)/(4)log_(e)|(4 sin theta+1)-sqrt(sin theta - cos 2 theta)|`D. `(1)/(2)sqrt(sin theta+cos2theta)+(3)/(4sqrt(2))log_(e)|4sintheta+1-sqrt(sintheta-cos2 theta)|`

But for all arbitrary constants, `intsqrt((1+sintheta-sin^(2)theta-sin

1.	But for all arbitrary constants, `intsqrt((1+sintheta-sin^(2)theta-sin^(3)theta)/(2sintheta-1))d theta` is equal toA. `(1)/(2)sqrt(sin theta-cos2 theta)+(3)/(4sqrt(2))log_(e)\|(4sintheta+1)+2sqrt(2)sqrt(sintheta-cos2theta)\|`B. `(1)/(2)sqrt(sintheta+cos2theta)+(3)/(4sqrt(2))log_(e)\|(4sin theta -1)+2sqrt(2)sqrt(sintheta+cos2 theta)\|`C. `(1)/(2sqrt(2))sqrt(sintheta-cos2 theta)+(3)/(4)log_(e)\|(4 sin theta+1)-sqrt(sin theta - cos 2 theta)\|`D. `(1)/(2)sqrt(sin theta+cos2theta)+(3)/(4sqrt(2))log_(e)\|4sintheta+1-sqrt(sintheta-cos2 theta)\|`
Answer» Correct Answer - a

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