By dissolving 0.35 mole of sodium chloride in water, 1.30 L of salt so

1.	By dissolving 0.35 mole of sodium chloride in water, 1.30 L of salt solution is obtained. The molarity of the resulting solution should be reported as(a) 0.3 M(b) 0.269 M(c) 0.27 M(d) 0.2692 M
Answer» Answer is : (c) 0.27 M Given, Number of moles of solute NaCl = 0.35 mole Volume of the solution = 1.30 L Molarity = (Number of moles of solute/Volume of solution in litres) = 0.35/1.30 = 0.269 ≈ 0.27 M

By dissolving 0.35 mole of sodium chloride in water, 1.30 L of salt solution is obtained. The molarity of the resulting solution should be reported as(a) 0.3 M(b) 0.269 M(c) 0.27 M(d) 0.2692 M

Answer»

Answer is : (c) 0.27 M

Given,

Number of moles of solute NaCl = 0.35 mole

Volume of the solution = 1.30 L

Molarity = (Number of moles of solute/Volume of solution in litres)

= 0.35/1.30 = 0.269 ≈ 0.27 M

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By dissolving 0.35 mole of sodium chloride in water, 1.30 L of salt solution is obtained. The molarity of the resulting solution should be reported as(a) 0.3 M(b) 0.269 M(c) 0.27 M(d) 0.2692 M

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