By dissolving 5 g substance in 50 g of water, the decrease in freezing point is `1.2^(@)C`. The gram molal depression is `1.85^(@)C`. The molecular weight of substance isA. `105.4`B. `118.2`C. `137.2`D. `154.2`

By dissolving 5 g substance in 50 g of water, the decrease in freezing

1.	By dissolving 5 g substance in 50 g of water, the decrease in freezing point is `1.2^(@)C`. The gram molal depression is `1.85^(@)C`. The molecular weight of substance isA. `105.4`B. `118.2`C. `137.2`D. `154.2`
Answer» Correct Answer - D We know that, `m=(1000 K_(f)xx w)/(Delta TW)` Here, `Delta T=1.2^(@)C, K_(f)=1.85^(@)` `w=5g, W=50 g` `m=(1000xx1.85xx5)/(1.2xx50)=154.2`.

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By dissolving 5 g substance in 50 g of water, the decrease in freezing point is `1.2^(@)C`. The gram molal depression is `1.85^(@)C`. The molecular weight of substance isA. `105.4`B. `118.2`C. `137.2`D. `154.2`

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