1.

By how much amount should the temperature of a steel rod be increased so that its length increases by 0.5%? The coefficient of linear expansion of steel is 1.2 xx 10^(-5) C^(-1)

Answer»

Solution :`(DELTA l)/(l) = (0.5)/(100) , ALPHA = 1.2 XX 10^(-5) ""^@C^(-1)`
`Delta T = ?`
` Delta l = alpha Delta T`
` Delta T = (Delta l)/(l alpha) = (0.5)/(100 xx 1.2 xx 10^(-5) ) = 416.7^@C`


Discussion

No Comment Found