1.

By passing `H_(2)S` in acidified `KMnO_(4)` solution we getA. `K_2S`B. SC. `K_2SO_3`D. `MnO_2`

Answer» Correct Answer - B
`KMnO_4//H^(+)` oxidises `H_2S` to S
`({:(2KMnO_4+3H_2SO_4to,K_2SO_4+2MnSO_4+3H_2O+50),(H_2S+O to, H_2O +S"]"xx5):})/ul(5H_2S + 2KMnO_4+3H_2SO_4 to 8H_2O + K_2SO_4 +2MnSO_4+5S)`


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