1.

By reduction of 1.27 gm Cu is obtained so what is the weight of oxygen.

Answer»

16 GM
8 gm
1.6 gm
0.16 gm

Solution :In `Cu_(2)O` weight of `Cu=127 gm = 1.27gm`
MASS of `O=15 gm = (?)`
`=(16 xx 1.27)/(127) =0.16 gm`


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