By the method of upsutra yavaduham Tavaduram find the square:(i) 93(ii

1.	By the method of upsutra yavaduham Tavaduram find the square:(i) 93(ii) 206(iii) 211(iv) 405
Answer» (i) 93 93² = 9(93 + 3)/(3)² = 9(96)/9 Base = 10 = 864/9 Sub-base = 10 × 9 8649 deviations = + 3 (ii) 206 206² = 2(206 + 06)/(06)² = 2(212)/36 Base = 100 = 424/36 Sub-base = 100 × 2 = 42436 deviation = +06 (iii) 211 211² =2(211 + 11)/(11)² = 2(222)₁21 Base = 100 = 444/₁21 Sub-base = 100 x 2 = 44521 deviation = +11 (iv) 405 405² = 4(405 + 05)/(05)² = 4(410) / 25 Base = 100 = 1640 / 25 Sub-base = 100 × 4 = 164025 deviation = +05

By the method of upsutra yavaduham Tavaduram find the square:(i) 93(ii) 206(iii) 211(iv) 405

Answer»

(i) 93

93² = 9(93 + 3)/(3)²

= 9(96)/9 Base = 10

= 864/9 Sub-base = 10 × 9

8649 deviations = + 3

(ii) 206

206² = 2(206 + 06)/(06)²

= 2(212)/36 Base = 100

= 424/36 Sub-base = 100 × 2

= 42436 deviation = +06

(iii) 211

211² =2(211 + 11)/(11)²

= 2(222)₁21 Base = 100

= 444/₁21 Sub-base = 100 x 2

= 44521 deviation = +11

(iv) 405

405² = 4(405 + 05)/(05)²

= 4(410) / 25 Base = 100

= 1640 / 25 Sub-base = 100 × 4

= 164025 deviation = +05