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By the reaction of carbon and oxygen, a mixture of CO and CO_(2) is obtained. What is the composition of the mixture by mass obtained when 20 grams of O_(2) reacts with 12 grams of carbon ? |
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Answer» `n_(c)=1` mole `(n_(O_(2)))/(n_(c))=0.625` `O_(2)+CrarrCO+CO_(2)` `2xxn_(O_(2))=n_(CO)+2n_(CO_(2))""......(I)` `2xxn_(C)=n_(CO)+n_(CO_(2))"".....(II)` `implies (n_(CO)xx28)/(n_(CO_(2))xx44)=(21)/(11)` |
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