1.

By the use of molecular orbital consideration, account for the fact that oxygen is paramagnetic.

Answer»

Solution :Electronic configuration of molecular orbitals of `O_(2)` is `(sigma1s)^(2)(SIGMA**1s)^(2)(sigma2s)^(2)(sigma**2S)^(2)(sigma2p_(Z))^(2)(pi2p_(x))^(2)`
`(pi2p_(y))^(2)(pi**2p_(x))^(1)(pi**2p_(x))^(1)`
The last two electrons are in `pi**2p_(x)` and `pi**2p_(y)` anti bonding orbitals so as to maximise pi electrons in accordance with Hund.s RULE. These two unpaired electrons confer paramagnetism in OXYGEN.


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