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By what acceleration the boy must go up so that `100kg` block remains stationary on the wedge. The wedge is fixed and is smooth `(g =10m//s^(2))` .A. `2 ms^(-2)`B. `4 ms^(-2)`C. `6 ms^(-2)`D. `8 ms^(-2)` |
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Answer» Correct Answer - C `100 g sin 30^(@) = 800 = T = 50 g + 50a` |
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