1.

By what factor does the average velocity of a gaseous molecule increase when the absolute temperature is doubled ?

Answer»

1.4
`2.0`
`2.8`
`4.0`

Solution :Average velocity `(vecc)=sqrt((8RT)/(PIM))`
If ABSOLUTE TEMPERATURE is doubled, new average velocity `=sqrt((8R.2T)/(piM))=sqrt(2)BAR(C )=1.4bar(c )`


Discussion

No Comment Found