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Answer» Solution Let the populations of VILLAGES X,A,B,C,D,E,F be x,a,b,c,d,e,f respectively Given that a = 0.25x b=0.2x c=0.4x d=0.6*0.4x=0.24x e=0.85*0.2x=0.17x f=0.35x=21000 Hece x = 60000 PER cent by which the POPULATION of village Eisless than that of village A = $(0.25x-0.17x)/0.25x \times 100$ =$0.08/0.25 \times 100 $ =32 |
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