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Answer»

Solution

Let the populations of VILLAGES X,A,B,C,D,E,F be x,a,b,c,d,e,f respectively

Given that

a = 0.25x

b=0.2x

c=0.4x

d=0.6*0.4x=0.24x

e=0.85*0.2x=0.17x

f=0.35x=21000

Hece x = 60000

PER cent by which the POPULATION of village Eisless than that of village A

= $(0.25x-0.17x)/0.25x \times 100$

=$0.08/0.25 \times 100 $

=32



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