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By what percentage should the pressure of a given mass of a gas be increased so as to decrease its volume by 10% at a constant temperature? |
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Answer» <P> SOLUTION :According to Boyle.s law,`(P+DELTAP)(V-DeltaV)=PV` `(P+DeltaP)(V-0.1V)=PV` `PV+V DeltaP-0.1PV-0.1VDeltaP=PV` `0.9V DeltaP=0.1PV` `(DeltaP)/(P)=(1)/(9)` `"Percentage increase"=(DeltaP)/(P)xx100=(100)/(9)=11.1` Percentage increase `=11.1%` |
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