1.

By what percentage should the pressure of a given mass of a gas be increased so as to decrease its volume by 10% at a constant temperature?

Answer»

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SOLUTION :According to Boyle.s law,
`(P+DELTAP)(V-DeltaV)=PV`
`(P+DeltaP)(V-0.1V)=PV`
`PV+V DeltaP-0.1PV-0.1VDeltaP=PV`
`0.9V DeltaP=0.1PV`
`(DeltaP)/(P)=(1)/(9)`
`"Percentage increase"=(DeltaP)/(P)xx100=(100)/(9)=11.1`
Percentage increase `=11.1%`


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