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By what percentage should the pressure of a given mass of a gas be increased so as to decrease its volume by 10% at a constant temperature? |
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Answer» According to boyle's law (P + ΔP) (V - ΔV) = PV (P + ΔP) (V - 0.1 V) = PV PV + VΔP - 0.1 PV - 0.1 VΔP = PV 0.9 V ΔP = 0.1 PV \(\frac{ΔP}{P}\) = \(\frac{1}{9}\) Percentage increase = \(\frac{ΔP}{P}\) x 100 = \(\frac{100}{9}\) = 11.1 Percentage increase = 11.1 % |
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