1.

c ) ^ 2 %2B ( c - a ) ^ 2 %2B ( b - d ) ^ 2 = ( a - d ) ^ 2

Answer»

(b-c)^2 + (c-a)^2 + (d-b)^2 = (a-d)^2

Let a = p, b = pr , c = pr² and d = pr³

Now, LHS = (b - c)² + (c - a)² + (d - b)² = (pr - pr²)² + (pr² - p)² + (pr³ - pr)² =( p²r² + p²r⁴ - 2p²r³) + (p²r⁴ + p² - 2p²r²) + (p²r^6 + p²r² -2p²r⁴) = p²r^6 - 2p²r³ + p²= (pr³) -2(pr³)(p) + p²= (pr³ - p)²= (p - pr³)² =(a - d)² = RHS

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