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`C_(6)H_(5)-O-CH_(3)+HI_((excess))rarr`A. `CH_(3)OH and C_(6)H_(5)I`B. `CH_(3)I and C_(6)H_(5)OH`C. `CH_(3)I and C_(6)H_(5)I`D. `C_(6)H_(6) and CH_(4)` |
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Answer» Correct Answer - B |
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