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(c)A 5 m long ladder is placed leaning towards a vertical wall such that it reaches the wall at a point 4m high. If the foot of the ladder is moved 1.6 m.towards the wall. Then find the distance by whichthe top of the ladder would slide up wards on thewall4 |
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Answer» Hypotneuse = 5 mBase = ?altitude = 4 mBase² = hyp² - alt²b² = 5² - 4²b² = 25 - 16b =√9b = 3 m When base is reduced by 1.6 mBase = 3 - 1.6 = 1.4 mhypotneuse = height of ladder = 5 maltitude = ? alt² = hyp²- base²alt² = 5² - 1.4²alt² = 25 - 1.96alt =√23.04alt = 4.8 m a |
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