C) A bullet having a mass of 10 g andmoving with a speed of 1.5 m/s,pe

1.	C) A bullet having a mass of 10 g andmoving with a speed of 1.5 m/s,penetrates a thick wooden plank ofmass 90 g. The plank was initiallyat rest. The bullet gets embedded inthe plank and both move togetherDetermine their velocity. only answer in short plz
Answer» Answer: 1.65 cm/s EXPLANATION: INITIAL momentum= m×u + m×0 = 10×10 × 1.5 = 15×10- ³ kg-m/s finial momentum= (m+M)×V = 910×10-³×v kg-m/s by CONSRVATION of momentum= 910×10-³×v = 15×10-³ hence, v= 15/910 ~ 0.0165m/s = 1.65 cm/s

C) A bullet having a mass of 10 g andmoving with a speed of 1.5 m/s,penetrates a thick wooden plank ofmass 90 g. The plank was initiallyat rest. The bullet gets embedded inthe plank and both move togetherDetermine their velocity. only answer in short plz

Answer»

Answer:

1.65 cm/s

INITIAL momentum= m×u + m×0 = 10×10 × 1.5 = 15×10- ³ kg-m/s

finial momentum= (m+M)×V = 910×10-³×v kg-m/s

by CONSRVATION of momentum= 910×10-³×v = 15×10-³

hence, v= 15/910 ~ 0.0165m/s = 1.65 cm/s