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C) A bullet having a mass of 10 g andmoving with a speed of 1.5 m/s,penetrates a thick wooden plank ofmass 900 g. The plank was initiallyat rest. The bullet gets embedded inthe plank and both move together.Determine their velocity.(Ans: 0.15 m/s) |
Answer» <html><body><p><strong>Answer:</strong></p><p></p><p><strong><a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> : </strong></p><p><strong>mass of bullet= <a href="https://interviewquestions.tuteehub.com/tag/10g-267074" style="font-weight:bold;" target="_blank" title="Click to know more about 10G">10G</a>= 0.01kg</strong></p><p><strong>velocity of bullet= 1.5m/s</strong></p><p><strong>mass of plank= 90g=0.09kg</strong></p><p><strong>Total momentum before collision=mass of plank x velocity</strong></p><p><strong>=0.01x1.5+0.09x0=0.015 kgm/s</strong></p><p><strong>Total momentum after collision=(mass of bullet +mass of plank )x velocity</strong></p><p><strong>=0.1 kg x V=0.1 V kgm/s</strong></p><p><strong>According to law of <a href="https://interviewquestions.tuteehub.com/tag/conservation-929810" style="font-weight:bold;" target="_blank" title="Click to know more about CONSERVATION">CONSERVATION</a> of momentum,</strong></p><p><strong>Total momentum before collision=Total momentum after collision</strong></p><p><strong>0.015kg m/s =0.1 v kg m/s</strong></p><p><strong>Thus,velocity <a href="https://interviewquestions.tuteehub.com/tag/acquired-1967529" style="font-weight:bold;" target="_blank" title="Click to know more about ACQUIRED">ACQUIRED</a> by the plank and the bullet = 0.15m/s</strong></p><p></p></body></html> | |