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C) A bullet having a mass of 10 g andmoving with a speed of 1.5 m/s,penetrates a thick wooden plank ofmass 900 g. The plank was initiallyat rest. The bullet gets embedded inthe plank and both move together.Determine their velocity.(Ans: 0.15 m/s) |
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Answer» Answer: GIVEN : mass of bullet= 10G= 0.01kg velocity of bullet= 1.5m/s mass of plank= 90g=0.09kg Total momentum before collision=mass of plank x velocity =0.01x1.5+0.09x0=0.015 kgm/s Total momentum after collision=(mass of bullet +mass of plank )x velocity =0.1 kg x V=0.1 V kgm/s According to law of CONSERVATION of momentum, Total momentum before collision=Total momentum after collision 0.015kg m/s =0.1 v kg m/s Thus,velocity ACQUIRED by the plank and the bullet = 0.15m/s |
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