1.

c) Solubility of AgCI is 1.3 x 10-5 mole/liter in water calculate the solubility ofAgCI in 10 KCI solution.

Answer»

AgCl(s)====>Ag+(aq) + Cl-(aq)

Ksp=[Ag+][Cl-]=(1.3x10^-5)²=1.7x10^-10



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