1.

C2H6(g)⇌C2H4(g)+H2(g) ;Kp=0.05 atm.The value of ΔG∘ of the reaction at 627 ∘C would be:(Given:ln(0.05)≈−3; R=8.3 J K−1 mol−1)

Answer» C2H6(g)C2H4(g)+H2(g) ;Kp=0.05 atm.

The value of ΔG of the reaction at 627 C would be:

(Given:ln(0.05)3; R=8.3 J K1 mol1)


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