C4H9Cl(A)KOH−−−−−−→(alcoholic)BBr2−−−→CCl4CNaNH2 – InterviewSolution

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1.	C4H9Cl(A)KOH−−−−−−→(alcoholic)BBr2−−−→CCl4CNaNH2−−−−−→(2 equiv)D[Ag(NH3)2]+−−−−−−−−→ppt.Number of secondary hydrogen atoms in (A) is:
Answer» $C_{4} H_{9} C l (A) K O H - ----- \to (alcoholic) B B r_{2} - -- \to C C l_{4} C N a N H_{2} - ---- \to (2 equiv) D [A g (N H_{3})_{2}]^{+} - ------- \to ppt.$ Number of secondary hydrogen atoms in (A) is:

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