CaCO_(3)(s)hArrCaO(s)+CO_(2)(g) CO_(2)(g)hArrCO(g)+(1)/(2)O_(2)(g) For above simultaneous equilibrium if CO_(2) is added from out side at equilibrium then:

CaCO_(3)(s)hArrCaO(s)+CO_(2)(g) CO_(2)(g)hArrCO(g)+(1)/(2)O_(2)(g) F

1.	CaCO_(3)(s)hArrCaO(s)+CO_(2)(g) CO_(2)(g)hArrCO(g)+(1)/(2)O_(2)(g) For above simultaneous equilibrium if CO_(2) is added from out side at equilibrium then:
Answer» `P_(CO_(2)` will increase `P_(CO_(2)` will decrease No shift in `2^(ND)` equilibrium BACKWARD shift in `1^(ST)` equilibrium Solution :Second equilibrium will not be affected by `CO_(2)` addition only first will shift backward.