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Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of `CO_2` will be obtained by thermal decomposition of 50g `CaCO_3` ?A. 1LB. 11.2 LC. 44 LD. 22.4 L

Answer» `underset(100g)(CaCO_3) to CaO + underset ("1 mole " = 22.4L)(CO_2)`
100g of `CaCO_3` at STP gives 22.4 L of `CO_2`
50g of `CaCO_3` will produce `(22.4)/(100)xx50=11.2L " of " CO_2`


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