Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction, CaCO3 (s) + 2HCl (aq) → CaCl2 (aq) + CO2 (g) + H2O (l). What mass of CaCO3 is required to react completely with 25 mL of 0.75 M HCl ?

Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 acco

1.	Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction, CaCO3 (s) + 2HCl (aq) → CaCl2 (aq) + CO2 (g) + H2O (l). What mass of CaCO3 is required to react completely with 25 mL of 0.75 M HCl ?
Answer» 1000 mL of.0.75 M HCl have 0.75 mol of HCl = 0.75 x 36.5 g = 24.375 g (Molar mass of HCl is 36.5) Mass of HCl in 25 mL of 0.75 M HCl = 24.375/1000 x 25 g = 0.6844 g According to the given chemical equation, CaCO₃ (s) + 2HCl(ag) →CaCl₂ (aq) + CO₂(g) + H₂O(Z) 2 mol of HCl i.e. 73 g HCl react completely with 1 mol of CaCO₃g i.e. 100 g .’. 0.6844 g HCl reacts completely with CaCO₃ = 100/73 x 0.6844 g = 0.938 g