Calcium carbons reacts with aqueous HCl to give CaCl2 and CO2 accordin

1.	Calcium carbons reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction given below:CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l)What mass of CaCl2 will be formed when 250 ml of 0.76 M HCl reacts with 1000 gm of CaCO3? Name the limiting reagent. Calculate the no. of moles of CaCl2 formed in the reaction.
Answer» CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + CO₂ (g) + H₂O(l) Number of moles of HCl = Volume in liters × Molarity = \(\frac{250}{1000}\) x 0.76 = 0.19 mol. Mass of CaCO₃ = 1000 g Number of moles of CaCO₃ = \(\frac{Mass}{Molar\,mass}\) = \(\frac{1000\,g}{100\,g\,mol^{-1}}\) 1 mole of CaCO₃ reacts with 2 moles of HCI 10 moles of CaCO₃ will react with 2 × 10 = 20 moles of HCl But, we have only 0.19 mol of HCl, therefore, HCl is the limiting reactant. 2 moles of HCI give 1 mole of CaCl₂ 0.19 mole of HCl will give = \(\frac{1}{2}\)x 0.19 = 0.095 moles of CaCl₂.

Calcium carbons reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction given below:CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l)What mass of CaCl2 will be formed when 250 ml of 0.76 M HCl reacts with 1000 gm of CaCO3? Name the limiting reagent. Calculate the no. of moles of CaCl2 formed in the reaction.

Answer»

CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + CO₂ (g) + H₂O(l)

Number of moles of HCl = Volume in liters × Molarity

= \(\frac{250}{1000}\) x 0.76 = 0.19 mol.

Mass of CaCO₃ = 1000 g

Number of moles of CaCO₃

= \(\frac{Mass}{Molar\,mass}\) = \(\frac{1000\,g}{100\,g\,mol^{-1}}\)

1 mole of CaCO₃ reacts with 2 moles of HCI

10 moles of CaCO₃ will react with 2 × 10 = 20 moles of HCl

But, we have only 0.19 mol of HCl, therefore,

HCl is the limiting reactant.

2 moles of HCI give 1 mole of CaCl₂

0.19 mole of HCl will give = \(\frac{1}{2}\)x 0.19

= 0.095 moles of CaCl₂.