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Calcium chlroide when dissolved in water dissociates into its ions according to the following equations. `CaCl_(2)(aq) to Ca^(2+)(aq) + 2Cl^(-1) (aq)` Calculate the number of ions obtained from `CaCl_(2)` when 222g of it is dissolved in water. |
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Answer» Molar mass of `CaCl_(2)=40+(2xx35.5)=111"g mol"^(-1)` `111"g of "CaCl_(2)"represent"=1"mol"` `222"g of "CaCl_(2)"represent"=((222g))/((111g))xx1"mol"=2"mol"` No. of molecules in 2 moles of `CaCl_(2)=2xxN_(A)=2xx6.022xx10^(23)` 1 molecules of `CaCl_(2)` in solution form ions =3 `2xx6.022xx10^(23)` molecules of `CaCl_(2)` in solution from ions `=3xx2xx6.022xx10^(23)` `=36.132xx10^(23)` `=3.6132xx10^(24)` |
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