Saved Bookmarks
| 1. |
Calculate 1. The number of molecules present in 1 g of water. 2. The volume of 0.2 mole of sulphur dioxide at STP. |
|
Answer» 1. Number of moles in 1 g water = \(\frac{1}{8}\) ∴ No. of molecules in 1 g water = \(\frac{1\times6.022\times10^{23}}{18}\) = 3.35 x 1022 2. Volume of 0.2 mol SO2 at STP = 0.2 × 22.4 litre = 4.48 litre |
|