1.

Calculate 1. The number of molecules present in 1 g of water. 2. The volume of 0.2 mole of sulphur dioxide at STP.

Answer»

1. Number of moles in 1 g water = \(\frac{1}{8}\)

∴ No. of molecules in 1 g water

\(\frac{1\times6.022\times10^{23}}{18}\) = 3.35 x 1022

2. Volume of 0.2 mol SO2 at STP = 0.2 × 22.4 litre 

= 4.48 litre



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