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Calculate (a) wave number and (b) frequency of yellow radiations having wavelength of `5800Å` |
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Answer» Calculate of wave number: Wave number `bar(v) = (1)/(lambda)` But `lamda = 5800Å = 5800 xx 10^(-10)m " (Given)" :. bar(v) = (1)/(5800 xx 10^(-10)m) = 1.72 xx 10^(6) m^(-1)` (b) Calculate of Frequency: Frequency `v = (c)/(lamda)` Substituting `c = 3 xx 10^(8) m//sec and lamda = 5800 xx 10^(-10)m`, we get `v = (3 xx 10^(8) ms^(-1))/(5800 xx 10^(-10)m) = 5.172 xx 10^(14) s^(-1)` or cycles/sec or Hz |
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