Calculate all the four quantum no. Of last electron of Cr

1.	Calculate all the four quantum no. Of last electron of Cr
Answer» Cr = 1s2 2s2 2p6 3s2 3p6 3d5 4s1. Therefore, last electron is in 3d orbital. Quantum numbers are :- n = 3.l = 2. ml = 2.ms = 1/2.

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