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InterviewSolution
| 1. |
calculate angular velocity of hand clock? |
| Answer» \tThe period of the hour hand of clock, T = 12 hours =\xa0{tex}12 \\times 60 \\times 60{/tex}\xa0seconds\tTherefore, Angular velocity of the hour hand of a clock, {tex}\\omega=\\frac{2 \\pi}{T}=\\frac{2 \\times 3.14}{12 \\times 60 \\times 60}{/tex}= 1.45\xa0{tex}\\times{/tex}\xa010-4\xa0rad s-1\tThe period of the second hand of clock, T = 1 minute = 60 seconds\tTherefore,\xa0Angular velocity of the second hand of a clock\xa0{tex}\\omega=\\frac{2 \\pi}{T}=\\frac{2 \\pi}{60}{/tex}= 0.105\xa0rad s-1<br>T to the power -1<br>T-1 | |