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Calculate coefficient of correlation from the following data: |
Answer» SOLUTION : `r=(sumdx'dy'-((sumdx') XX(sumdy'))/(N))/(sqrt(sumdx'^(2)=((sumdx')^(2))/(N))xx sqrt(sumdy'^(2)-((sumdy')^(2))/(N)))` `=(42-((3)xx(4))/(6))/(sqrt(19-((3)^(2))/(6))xxsqrt(196-((4)^(2))/(6)))` `=(42-2)/(sqrt(19-1.5)xxsqrt(96-2.67))` `=(40)/(sqrt(17.5)xxsqrt(93.33))` `=(40)/(4.18xx9.66)=(40)/(40.3788)=0.99` Coefficient of Correlation (r)=0.99 |
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