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Calculate conc. of oh- in 0.01m sol. of Nh3 if kb =1.76*10^-5 |
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Answer» The Henderson-Hasselbalch EQUATION STATES that pOH = pKb + log([salt]/[BASE]). Hence, assuming you know the values of [salt] and [base], you can take the negative log of Kb. ADDING pKb and log([salt]/[base]) will then give you your pOH value. From there, subtract pOH from 14 to find pH as pH + pOH = 14. |
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