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Calculate d^2i(0)/dt^2 from the given circuit.(a) 10^-6A/s^2(b) 10^-3A/s^2(c) 10^6A/s^2(d) 10^3A/s^2 |
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Answer» The correct answer is (b) 10^-3A/s^2 The best explanation: Applying KVL to the given circuit, we get: 100+10i(0)+1/10*integral(i(0)dt)=0 Differentiating once, we get: 10di(0)/dt+1/10*i. Differentiating once again, we get: 10d^2i(0)/dt^2+10di(0)/dt=0. Substituting the values of di/dt from the previous explanation, we get d^2i(0)/dt^2=10^-3A/s^2. |
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