Calculate `Delta ,G^@` and log `K_c` for the following reation: `Cd^(+2)(aq)+Zn^(2+)(aq)+Cd(s)` Given : `E_(cd^(2+)//cd)^(0)=0.403 V` `E_(Zn^2+//Zn)^(0)=0.763 V`

Calculate `Delta ,G^@` and log `K_c` for the following reation: `Cd^(+

1.	Calculate `Delta ,G^@` and log `K_c` for the following reation: `Cd^(+2)(aq)+Zn^(2+)(aq)+Cd(s)` Given : `E_(cd^(2+)//cd)^(0)=0.403 V` `E_(Zn^2+//Zn)^(0)=0.763 V`
Answer» `E^@ "cell"= E^@C-E^@ a ` `=-0.403-(0.763)=0.360 V ` `log K_c=(nE_("cell"^(@))/(0.059))=((2xx 0.360)/(0.059))=((0.720)/(0.059))=12.20` (ii) `Delta G^@=-nFE_"cell"^(@)=-2xx96500xx0.360=-69480` J

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Calculate `Delta ,G^@` and log `K_c` for the following reation: `Cd^(+2)(aq)+Zn^(2+)(aq)+Cd(s)` Given : `E_(cd^(2+)//cd)^(0)=0.403 V` `E_(Zn^2+//Zn)^(0)=0.763 V`

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