1.

Calculate Delta H_(f) of HCl if bond energy of H-H bond is 437 kJ Cl-CL bond is 244, and H-C is 433 kJ mol^(-1).

Answer»

Solution :`(1)/(2)H_(2)(G) + (1)/(2)Cl_(2)(g) rarr HCl(g)`
`Delta H = (1)/(2)B_(H-H) + (1)/(2)B_(O-O) = (1)/(2) XX 437 + (1)/(2) xx 244 - 433`
`= 218.5 kJ + 122 kJ - 433 kJ = -92.5 kJ mol^(-1)`.


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