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Calculate Delta_(r )G^(@) for the reaction for which the value of K_(p) is 1.5 xx 10^(10) at 300 K. |
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Answer» <P> Solution :`Delta G^(@) = -2.303 RT log_(10)K_(p)``= -2.303 XX 8.314 xx 300 xx log 1.5 xx 10^(10)` `= -2.303 xx 8.314 xx 300 xx (log 1.5 + log 10^(10))` `= -2.303 xx 8.314 xx 300 xx (0.1761 + 10)` `= -2.303 xx 8.314 xx 300 xx 10.1761 = 58452.97 J mol^(-1)`. `= -57270 J` |
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