InterviewSolution
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InterviewSolution
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Calculate `DeltaG_(298)^(@)` and `DeltaS_(298)^(@)` for the reaction : `2H_(2(g))+O_(2(g)) rarr 2H_(2)O_((l)): DeltaH_(298)^(@) = -136.64kcal`. Given that `O_(2(g))+4H^(+)+4e rarr 2H_(2)O_((l)), E^(@) = 1.23V` `2H_(2(g)) rarr 4H^(+)+4e, E^(@) = 0.00V` |
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Answer» Given `{:(O_(2(g))+4H^(+)+4erarr2H_(2)O_(4), E^(@)=1.23V),(2H_(2(g))rarr4H^(+)+e^(-), E^(@)=0.00V):} /("On adding" 2H_(2(g))+O_(2(g))rarr2H_(2)O_((l)))` , `E^(@)=1.23+0 = 1.23V)` `because DeltaG_(298)^(@) = -nE^(@)F` `= 4 xx 1.23 xx 96500 = -474780J` `= -474.78J = -113.58 kcal` Also `DeltaG_(298)^(@) = DeltaH^(@)-TDeltaS^(@)` `DeltaS_(298)^(@) = [(DeltaG^(@)-DeltaH^(@))/(T)]= (DeltaH^(@)-DeltaG^(@))/(T)` `= (-136.64-(-113.58))/(298)` `= -0.77 kcal` |
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