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Calculate DeltaG and DeltaG^(@) for the reaction :A + B hArr C + Dat 27^(@)C .Equilibrium constnat(K) for this reaction = 10^(2) |
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Answer» Solution :`DeltaG = 0` because the reactin is in equilibrium. `DeltaG^(@) = - 2.303 RT logK = -2.303 XX 8.314 JK^(-1) MOL^(-1) xx 300 K log 10^(2)` `= - 1148 J mol^(-1) = - 11.488 kJ mol^(-1)` |
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