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Calculate ΔfH° (In kJ/mol) for C2H6(g), if ΔcH° [C(graphite)] = –393.5 kJ/mol,ΔCHº [H2(g)] = –286 kJ/mol and ΔCHº [C6H6(g)] = –1560 kJ/mol |
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Answer» The answer is (–85.00) C6H2(g) + 3.5O2(g) →2CO2(g) + 3H2O(l) 2 × (–393.5) + 3 × (–286) – (–1560) = –85 kJ/mol |
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