Calculate distance of closet approach by an alpha -particle of KE=2.5 MeV being scattered by gold nucleus (Z=79).

Calculate distance of closet approach by an alpha -particle of KE=2.5

1.	Calculate distance of closet approach by an alpha -particle of KE=2.5 MeV being scattered by gold nucleus (Z=79).
Answer» Solution :`KE_(i) PE_(F) = (K(79e)(2e))/(r )` Remember : `(1eV=1.6xx10^(-19)J)/(1MeV=1.6xx10^(-13)J)` `implies 2.5xx1.6xx10^(-13)J=(9xx10^(9)xx79xx2xx(1.6xx10^(-19))^(2))/(r )implies r = 9.1xx10^(-14)m`