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Calculate ΔSsurr when on mole of methanol (CH3OH) is formed from its elements under standard conditions if ΔfH0(CH3OH) = -238.9 J mol-1. |
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Answer» Given : Number of moles of ethanol, (C2H5OH) = n = 1 mol ΔfH0(CH3OH) = -238.9 kJ mol-1 = -238.9 × 103J mol-1 Temperature = T = 298 K ΔS = ? ΔSsurr = ? Since ΔfH0 is negative, The reaction for the formation of one mole of C2H5OH is exothermic. As heat is released to the surroundings, ΔH0surr = + 238.9 kJ mol-1 ∴ ΔSsurr = \(\frac{ΔH^0_{surr}}{T}\) = \(\frac{+238.9\times 10^3}{298}\) = +801.7JK-1 Thus, Entropy of the surroundings increases. ∴ ΔSsurr = +801.7JK-1 |
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